10x^2+60x=72

Solution for 10x^2+60x=72 equation:

10x^2+60x=72

We move all terms to the left:

10x^2+60x-(72)=0

a = 10; b = 60; c = -72;
Δ = b2-4ac
Δ = 602-4·10·(-72)
Δ = 6480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6480}=\sqrt{1296*5}=\sqrt{1296}*\sqrt{5}=36\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-36\sqrt{5}}{2*10}=\frac{-60-36\sqrt{5}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+36\sqrt{5}}{2*10}=\frac{-60+36\sqrt{5}}{20}
$